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Postby SSBubbles » Thu Jul 03, 2008 3:45 pm

denizaksulu wrote:
SSBubbles wrote:
denizaksulu wrote:............................................a place in Arizona? (hint?)



Deniz, I have not had a drink all week, but you certainly leave me needing one! Kindly explain :? :?



Phoen..Arizona. I am not allowed to go further. USA city. ?




Blame the heat - (but I thought that was further south??) :lol: :roll:
Last edited by SSBubbles on Thu Jul 03, 2008 3:47 pm, edited 1 time in total.
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Postby SSBubbles » Thu Jul 03, 2008 3:46 pm

tessintrnc wrote:never!! (I feel very stupid - I said philedelphia instead of phoenix - never good at geography - but love living here in France!!!!!)



:lol: :lol: :lol:

error!
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Postby tessintrnc » Thu Jul 03, 2008 3:47 pm

original
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Postby denizaksulu » Thu Jul 03, 2008 3:49 pm

algebraic
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Postby tessintrnc » Thu Jul 03, 2008 3:58 pm

ice (are you making these up?)
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Postby denizaksulu » Thu Jul 03, 2008 4:15 pm

[quote="tessintrnc"]ice (are you making these up?)[/quote]


here you are O educated one. Remember?

Algebraic Fractions
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[color=red]Algebraic Fractions[/color]
When adding or subtracting algebraic fractions, the first thing to do is to put them onto a common denominator (by cross multiplying).

e.g. 1 + 4
(x + 1) (x + 6)

= 1(x + 6) + 4(x + 1)
(x + 1)(x + 6)

= x + 6 + 4x + 4
(x + 1)(x + 6)

= 5x + 10
(x + 1)(x + 6)


Solving equations
When solving equations containing algebraic fractions, first multiply both sides by a number/expression which removes the fractions.

Example:
Solve 10 - 2 = 1
(x + 3) x

multiply both sides by x(x + 3):
\ 10x(x + 3) - 2x(x + 3) = x(x + 3)
(x + 3) x

\ 10x - 2(x + 3) = x² + 3x [after cancelling]
\ 10x - 2x - 6 = x² + 3x
\ x² - 5x + 6 = 0
\ (x - 3)(x - 2) = 0
\ either x = 3 or x = 2
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Postby SSBubbles » Thu Jul 03, 2008 4:18 pm

denizaksulu wrote:
tessintrnc wrote:ice (are you making these up?)



here you are O educated one. Remember?

Algebraic Fractions
Bookmark this page

Algebraic Fractions
When adding or subtracting algebraic fractions, the first thing to do is to put them onto a common denominator (by cross multiplying).

e.g. 1 + 4
(x + 1) (x + 6)

= 1(x + 6) + 4(x + 1)
(x + 1)(x + 6)

= x + 6 + 4x + 4
(x + 1)(x + 6)

= 5x + 10
(x + 1)(x + 6)


Solving equations
When solving equations containing algebraic fractions, first multiply both sides by a number/expression which removes the fractions.

Example:
Solve 10 - 2 = 1
(x + 3) x

multiply both sides by x(x + 3):
\ 10x(x + 3) - 2x(x + 3) = x(x + 3)
(x + 3) x

\ 10x - 2(x + 3) = x² + 3x [after cancelling]
\ 10x - 2x - 6 = x² + 3x
\ x² - 5x + 6 = 0
\ (x - 3)(x - 2) = 0
\ either x = 3 or x = 2



Excuse me mister, but I don't do 'maffs'! :roll: :wink:
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Postby denizaksulu » Thu Jul 03, 2008 4:23 pm

SSBubbles wrote:
denizaksulu wrote:
tessintrnc wrote:ice (are you making these up?)



here you are O educated one. Remember?

Algebraic Fractions
Bookmark this page

Algebraic Fractions
When adding or subtracting algebraic fractions, the first thing to do is to put them onto a common denominator (by cross multiplying).

e.g. 1 + 4
(x + 1) (x + 6)

= 1(x + 6) + 4(x + 1)
(x + 1)(x + 6)

= x + 6 + 4x + 4
(x + 1)(x + 6)

= 5x + 10
(x + 1)(x + 6)


Solving equations
When solving equations containing algebraic fractions, first multiply both sides by a number/expression which removes the fractions.

Example:
Solve 10 - 2 = 1
(x + 3) x

multiply both sides by x(x + 3):
\ 10x(x + 3) - 2x(x + 3) = x(x + 3)
(x + 3) x

\ 10x - 2(x + 3) = x² + 3x [after cancelling]
\ 10x - 2x - 6 = x² + 3x
\ x² - 5x + 6 = 0
\ (x - 3)(x - 2) = 0
\ either x = 3 or x = 2



Excuse me mister, but I don't do 'maffs'! :roll: :wink:



Sorry miss, I dont make 'em up :lol:
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Postby perdike » Thu Jul 03, 2008 4:25 pm

Kiss and make-up?
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Postby denizaksulu » Thu Jul 03, 2008 4:32 pm

perdike wrote:Kiss and make-up?


Yes please :lol:
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